Reagent X in the given reaction is:(Image sho | vedclass

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(B) The reaction involves the reduction of a ketone (cyclohexanone) to an alcohol.In the reduction of a carbonyl group using $LiAlH_4$ or $LiAlD_4$,th

Vedclass · Accepted Answer

$LiAlD_4 + H_2O$

Vedclass · Answer

(B) The reaction involves the reduction of a ketone (cyclohexanone) to an alcohol.In the reduction of a carbonyl group using $LiAlH_4$ or $LiAlD_4$,the hydride $(H^-)$ or deuteride $(D^-)$ ion from the metal hydride reagent attacks the electrophilic carbonyl carbon.Subsequently,the oxygen atom is protonated or deuterated during the workup step using water $(H_2O)$ or heavy water $(D_2O)$.In the product,the carbon atom is bonded to a hydroxyl group $(-OH)$ and a deuterium atom $(-D)$.This indicates that the deuterium atom was added during the reduction step (from the reagent) and the hydrogen atom was added during the workup step (from the water).Therefore,the reagent $X$ must be $LiAlD_4$ followed by $H_2O$.

Reagent $X$ in the given reaction is:
(Image shows cyclohexanone being converted to cyclohexanol with a deuterium atom attached to the same carbon as the hydroxyl group.)

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Reagent $X$ in the given reaction is:(Image shows cyclohexanone being converted to cyclohexanol with a deuterium atom attached to the same carbon as the hydroxyl group.)