Reagent A may be: | vedclass

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Question

(C) The reaction shows the hydration of an alkene to form a secondary alcohol. $1$. Acid-catalyzed hydration $(H_2O/H^{+})$ would involve a carbocatio

Vedclass · Accepted Answer

$Hg(OCOCH_3)_2 \cdot H_2O/NaBH_4 \cdot NaOH$

Vedclass · Answer

(C) The reaction shows the hydration of an alkene to form a secondary alcohol. $1$. Acid-catalyzed hydration $(H_2O/H^{+})$ would involve a carbocation intermediate,which would rearrange to form a more stable benzylic carbocation,leading to a different product. $2$. Hydroboration-oxidation $(BH_3 \cdot THF/H_2O_2-OH^{-})$ follows anti-Markovnikov addition,which would yield a primary alcohol. $3$. Oxymercuration-demercuration $(Hg(OCOCH_3)_2 \cdot H_2O/NaBH_4 \cdot NaOH)$ follows Markovnikov's rule without carbocation rearrangement,yielding the observed secondary alcohol. Therefore,the correct reagent is $(C)$.

Reagent $A$ may be:

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