Reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution results in the formation of the following compound:

  • A
    hydrazobenzene
  • B
    azobenzene
  • C
    aniline
  • D
    phenyl hydroxyl amine

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What is obtained when nitrobenzene is treated sequentially with $(i)$ $NH_4Cl / Zn$ dust and $(ii)$ $H_2SO_4 / Na_2Cr_2O_7$?

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