The relation between (B) and (C) is:CH_3-C eq | vedclass

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(D) Step $1$: Formation of $(A)$. The reaction of propyne with $NaNH_2$ followed by $CH_3-I$ yields but$-2-$yne $(CH_3-C \equiv C-CH_3)$ as $(A)$.Step

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Both $(b)$ and $(c)$

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(D) Step $1$: Formation of $(A)$. The reaction of propyne with $NaNH_2$ followed by $CH_3-I$ yields but$-2-$yne $(CH_3-C \equiv C-CH_3)$ as $(A)$.Step $2$: Formation of $(B)$. Reduction of but$-2-$yne with $Li/liq. NH_3$ (Birch reduction) gives trans-but$-2-$ene as $(B)$.Step $3$: Formation of $(C)$. Reduction of but$-2-$yne with $H_2/Pd-CaCO_3$ (Lindlar's catalyst) gives cis-but$-2-$ene as $(C)$.Step $4$: Relation between $(B)$ and $(C)$. Since $(B)$ is trans-but$-2-$ene and $(C)$ is cis-but$-2-$ene,they are geometrical isomers. Geometrical isomers are a type of diastereomer. Therefore,both $(b)$ and $(c)$ are correct.

The relation between $(B)$ and $(C)$ is:
$CH_3-C \equiv CH$ $\xrightarrow{NaNH_2}$ $\xrightarrow{CH_3-I} (A)$ $\xrightarrow{Li/liq. NH_3} (B)$
$CH_3-C \equiv CH$ $\xrightarrow{NaNH_2}$ $\xrightarrow{CH_3-I} (A)$ $\xrightarrow[Pd/CaCO_3]{H_2} (C)$

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The relation between $(B)$ and $(C)$ is:$CH_3-C \equiv CH$ $\xrightarrow{NaNH_2}$ $\xrightarrow{CH_3-I} (A)$ $\xrightarrow{Li/liq. NH_3} (B)$$CH_3-C \equiv CH$ $\xrightarrow{NaNH_2}$ $\xrightarrow{CH_3-I} (A)$ $\xrightarrow[Pd/CaCO_3]{H_2} (C)$