Represent $\sqrt{4.5}$ geometrically on the number line.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) $1$. Draw a line segment $AB = 4.5$ units on a number line.
$2$. From point $B$,mark a distance of $1$ unit and label the new point as $C$. Now,$AC = 4.5 + 1 = 5.5$ units.
$3$. Find the midpoint of $AC$ and label it as $O$.
$4$. Draw a semicircle with center $O$ and radius $OC$ (or $OA$).
$5$. Draw a line perpendicular to $AC$ at point $B$,which intersects the semicircle at point $D$. The length of $BD$ is $\sqrt{4.5}$.
$6$. With $B$ as the center and $BD$ as the radius,draw an arc that intersects the number line at point $E$. The point $E$ represents $\sqrt{4.5}$ on the number line.

Explore More

Similar Questions

Find the value of the following expression correct to three decimal places,rationalizing the denominator if needed. Take $\sqrt{2} = 1.414$,$\sqrt{3} = 1.732$,and $\sqrt{5} = 2.236$.
$\frac{4}{3 \sqrt{3}-2 \sqrt{2}} + \frac{3}{3 \sqrt{3}+2 \sqrt{2}}$

Difficult
View Solution

If $(\frac{2}{5})^{5} \times (\frac{25}{4})^{3} = (\frac{5}{2})^{3x-2}$,then find $x$.

Simplify: $(3 \sqrt{5}-5 \sqrt{2})(4 \sqrt{5}+3 \sqrt{2})$

Difficult
View Solution

Rationalise the denominator of the following:
$\frac{\sqrt{6}}{\sqrt{2}+\sqrt{3}}$

Difficult
View Solution

Rationalise the denominator in each of the following and hence evaluate by taking $\sqrt{2}=1.414, \sqrt{3}=1.732$ and $\sqrt{5}=2.236,$ up to three decimal places.
$\frac{1}{\sqrt{3}+\sqrt{2}}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo