Represent the structure of the free radical,carbocation,and carbanion derived from methane.

(N/A) The formation of reactive intermediates from methane $(CH_4)$ occurs via bond cleavage:
$1$. Homolytic cleavage: The covalent bond breaks equally,resulting in the formation of a methyl free radical $(CH_3^{\bullet})$ and a hydrogen radical $(H^{\bullet})$.
$2$. Heterolytic cleavage: The covalent bond breaks unequally,where the shared electron pair stays with one fragment.
- If the carbon atom retains the electron pair,a methyl carbanion $(CH_3^-)$ and a proton $(H^+)$ are formed.
- If the hydrogen atom retains the electron pair,a methyl carbocation $(CH_3^+)$ and a hydride ion $(H:^-)$ are formed.