Represent the following data by a bar graph:
Name of student Kavya Ariv Ahaan Arya Arushi Marks scored $90$ $80$ $50$ $60$ $40$
| Name of student | Kavya | Ariv | Ahaan | Arya | Arushi |
| Marks scored | $90$ | $80$ | $50$ | $60$ | $40$ |
(N/A) To represent the data using a bar graph,follow these steps:
$1$. Draw two perpendicular axes: the horizontal axis ($x$-axis) and the vertical axis ($y$-axis).
$2$. Along the $x$-axis,mark the names of the students (Kavya,Ariv,Ahaan,Arya,Arushi) at equal intervals.
$3$. Along the $y$-axis,choose a suitable scale to represent the marks scored. For example,$1 \text{ unit} = 10 \text{ marks}$.
$4$. Draw bars of equal width for each student,with heights corresponding to their respective marks:
- Kavya: $90$
- Ariv: $80$
- Ahaan: $50$
- Arya: $60$
- Arushi: $40$
$5$. Ensure there is equal spacing between the bars.
$1$. Draw two perpendicular axes: the horizontal axis ($x$-axis) and the vertical axis ($y$-axis).
$2$. Along the $x$-axis,mark the names of the students (Kavya,Ariv,Ahaan,Arya,Arushi) at equal intervals.
$3$. Along the $y$-axis,choose a suitable scale to represent the marks scored. For example,$1 \text{ unit} = 10 \text{ marks}$.
$4$. Draw bars of equal width for each student,with heights corresponding to their respective marks:
- Kavya: $90$
- Ariv: $80$
- Ahaan: $50$
- Arya: $60$
- Arushi: $40$
$5$. Ensure there is equal spacing between the bars.
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Similar Questions
The following are the marks (out of $100$) of $60$ students in mathematics:
$16, 13, 5, 80, 86, 7, 51, 48, 24, 56, 70, 19, 61, 17, 16, 36, 34, 42, 34, 35, 72, 55, 75, 31, 52, 28, 72, 97, 74, 45, 62, 68, 86, 35, 85, 36, 81, 75, 55, 26, 95, 31, 7, 78, 92, 62, 52, 56, 15, 63, 25, 36, 54, 44, 47, 27, 72, 17, 4, 30$
Construct a grouped frequency distribution table with a width of $10$ for each class,starting from $0-9$.
$16, 13, 5, 80, 86, 7, 51, 48, 24, 56, 70, 19, 61, 17, 16, 36, 34, 42, 34, 35, 72, 55, 75, 31, 52, 28, 72, 97, 74, 45, 62, 68, 86, 35, 85, 36, 81, 75, 55, 26, 95, 31, 7, 78, 92, 62, 52, 56, 15, 63, 25, 36, 54, 44, 47, 27, 72, 17, 4, 30$
Construct a grouped frequency distribution table with a width of $10$ for each class,starting from $0-9$.
Medium
View Solution$A$ grouped frequency distribution table with classes of equal sizes using $63-72$ ($72$ included) as one of the class is constructed for the following data:
$30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88$
$40, 14, 20, 15, 35, 44, 66, 75, 84, 95, 96$
$102, 110, 88, 74, 112, 14, 34, 44$
The number of classes in the distribution will be:
$30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88$
$40, 14, 20, 15, 35, 44, 66, 75, 84, 95, 96$
$102, 110, 88, 74, 112, 14, 34, 44$
The number of classes in the distribution will be:
Easy
View SolutionThe difference of the highest and the lowest values in the data is called the ............
Easy
View SolutionObservations of a data are $28, 16, 9, 17, 82, 71, 41, 18, 25, 15$. Find the range of the data.
Easy
View Solution$A$ football player scored the following number of goals in $10$ matches:
$1, 3, 2, 5, 8, 6, 1, 4, 7, 9$
Since the number of matches is $10$ (an even number),the median is calculated as:
Median $= \frac{5^{\text{th}} \text{ observation} + 6^{\text{th}} \text{ observation}}{2}$
$= \frac{8 + 6}{2} = 7$
Is this the correct answer? If not,why?
$1, 3, 2, 5, 8, 6, 1, 4, 7, 9$
Since the number of matches is $10$ (an even number),the median is calculated as:
Median $= \frac{5^{\text{th}} \text{ observation} + 6^{\text{th}} \text{ observation}}{2}$
$= \frac{8 + 6}{2} = 7$
Is this the correct answer? If not,why?
Medium
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