Represent the following situation mathematically:
John and Jivanti together have $45$ marbles. Both of them lost $5$ marbles each,and the product of the number of marbles they now have is $124$. We would like to find out how many marbles they had to start with.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) Let the number of marbles John had be $x$.
Then the number of marbles Jivanti had $= 45 - x$.
The number of marbles left with John after losing $5$ marbles $= x - 5$.
The number of marbles left with Jivanti after losing $5$ marbles $= (45 - x) - 5 = 40 - x$.
According to the problem,the product of the remaining marbles is $124$:
$(x - 5)(40 - x) = 124$.
Expanding the product:
$40x - x^2 - 200 + 5x = 124$
$-x^2 + 45x - 200 = 124$
Rearranging the terms to form a standard quadratic equation:
$-x^2 + 45x - 200 - 124 = 0$
$-x^2 + 45x - 324 = 0$
Multiplying by $-1$:
$x^2 - 45x + 324 = 0$.
Thus,the number of marbles John had satisfies the quadratic equation $x^2 - 45x + 324 = 0$.

Explore More

Similar Questions

Find two consecutive positive integers,the sum of whose squares is $365$.

Find the roots of the following equation:
$\frac{1}{x+4}-\frac{1}{x-7}=\frac{11}{30}, x \neq -4, 7$

Difficult
View Solution

Sum of the areas of two squares is $468 \, m^2$. If the difference of their perimeters is $24 \, m$,find the sides of the two squares.

Find the roots of the following quadratic equation by factorisation:
$2x^{2} + x - 6 = 0$

Find the discriminant of the equation $3x^{2}-2x+\frac{1}{3}=0$ and hence find the nature of its roots. Find them,if they are real.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo