The same current is flowing in two alternatin | vedclass

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Question

(D) The current in an inductive circuit is given by $I_{L} = \frac{V}{X_{L}}$,where $X_{L} = \omega L = 2\pi f L$. Thus,$I_{L} = \frac{V}{2\pi f L}$.

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Decreases in the first circuit and increases in the other

Vedclass · Answer

(D) The current in an inductive circuit is given by $I_{L} = \frac{V}{X_{L}}$,where $X_{L} = \omega L = 2\pi f L$. Thus,$I_{L} = \frac{V}{2\pi f L}$. As frequency $f$ increases,$X_{L}$ increases,so $I_{L}$ decreases.The current in a capacitive circuit is given by $I_{C} = \frac{V}{X_{C}}$,where $X_{C} = \frac{1}{\omega C} = \frac{1}{2\pi f C}$. Thus,$I_{C} = V(2\pi f C)$. As frequency $f$ increases,$X_{C}$ decreases,so $I_{C}$ increases.Therefore,the current decreases in the first circuit (inductor) and increases in the second circuit (capacitor).

The same current is flowing in two alternating circuits. The first circuit contains only an inductor,and the second contains only a capacitor. If the frequency of the $e.m.f.$ of the $ac$ source is increased,what will be the effect on the value of the current in these circuits?

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