The same current is flowing in two alternatin | vedclass

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(D) For the first circuit (inductor only),the current is given by $i = \frac{V}{X_L} = \frac{V}{\omega L} = \frac{V}{2\pi f L}$.As the frequency $f$ i

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Decreases in the first circuit and increases in the other

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(D) For the first circuit (inductor only),the current is given by $i = \frac{V}{X_L} = \frac{V}{\omega L} = \frac{V}{2\pi f L}$.As the frequency $f$ increases,the inductive reactance $X_L = 2\pi f L$ increases,which causes the current $i$ to decrease.For the second circuit (capacitor only),the current is given by $i = \frac{V}{X_C} = V\omega C = V(2\pi f)C$.As the frequency $f$ increases,the capacitive reactance $X_C = \frac{1}{2\pi f C}$ decreases,which causes the current $i$ to increase.Therefore,the current decreases in the first circuit and increases in the second circuit.

The same current is flowing in two alternating circuits. The first circuit contains only an inductor and the second contains only a capacitor. If the frequency of the $e.m.f.$ of the $ac$ source is increased,what will be the effect on the value of the current in these circuits?

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