See the electrical circuit shown in the figur | vedclass

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(B) Applying Kirchhoff's Voltage Law $(KVL)$ to the upper loop containing the resistor $R$ and the cell with emf ${\varepsilon _1}$ and internal resis

Vedclass · Accepted Answer

${\varepsilon _1} - ({i_1} + {i_2})R - {i_1}{r_1} = 0$

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(B) Applying Kirchhoff's Voltage Law $(KVL)$ to the upper loop containing the resistor $R$ and the cell with emf ${\varepsilon _1}$ and internal resistance ${r_1}$:Starting from the positive terminal of the cell ${\varepsilon _1}$ and moving in the direction of the current:$1$. The potential drop across the cell is ${\varepsilon _1}$.$2$. The current flowing through the resistor $R$ is $(i_1 + i_2)$,so the potential drop is $-(i_1 + i_2)R$.$3$. The current flowing through the internal resistance $r_1$ is $i_1$,so the potential drop is $-i_1r_1$.Summing these potential changes to zero gives: ${\varepsilon _1} - (i_1 + i_2)R - i_1r_1 = 0$.

See the electrical circuit shown in the figure. Which of the following equations is a correct equation for it?

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