Select the correct order - | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to Molecular Orbital Theory $(MOT)$,the bond order is calculated as $	ext{Bond Order} = \frac{N_b - N_a}{2}$.For $O_2^{2-}$ ($18$ elect

Vedclass · Accepted Answer

All

Vedclass · Answer

(D) According to Molecular Orbital Theory $(MOT)$,the bond order is calculated as $	ext{Bond Order} = \frac{N_b - N_a}{2}$.For $O_2^{2-}$ ($18$ electrons): Bond order $= 1$,unpaired electrons $= 0$.For $O_2^{-}$ ($17$ electrons): Bond order $= 1.5$,unpaired electrons $= 1$.For $O_2$ ($16$ electrons): Bond order $= 2$,unpaired electrons $= 2$.For $O_2^{+}$ ($15$ electrons): Bond order $= 2.5$,unpaired electrons $= 1$.$1$. Bond length is inversely proportional to bond order: $O_2^{2-} (1) > O_2^{-} (1.5) > O_2 (2) > O_2^{+} (2.5)$. This is correct.$2$. Bond strength is directly proportional to bond order: $O_2^{+} (2.5) > O_2 (2) > O_2^{-} (1.5) > O_2^{2-} (1)$. This is correct.$3$. Number of unpaired electrons: $O_2 (2) > O_2^{+} (1) = O_2^{-} (1) > O_2^{2-} (0)$. This is correct.Since all statements are correct,the answer is $D$.

Select the correct order $-$

Similar Questions

Paramagnetism is exhibited by molecules:

Which of the following is paramagnetic?

If the sum of bond orders of $O_2^{-}$ and $O_2^{2-}$ is $x$,then bond order of $O_2^{2+}$ will be (in $x$)

Answer the following questions:
$(i)$ Give the molecular orbitals and their types formed by $LCAO$ from $2s, 2p_{x}, 2p_{y}$ and $2p_{z}$ atomic orbitals.
$(ii)$ Provide the energy order of molecular orbitals for $Li_{2}, Be_{2}, C_{2}, N_{2}, O_{2}$ and $F_{2}$.

Which of the following is correctly matched?

Vedclass Test Series

Exam Paper Generator

Online Exam Module