Select the odd one w.r.t. EAN :- | vedclass

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Question

(B) The formula for Effective Atomic Number $(EAN)$ is:$EAN = Z - 	ext{Oxidation State} + 2 	imes 	ext{Coordination Number}$For $[Fe(CO)_5]$: $EAN

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$[Cr(CN)_6]^{-3}$

Vedclass · Answer

(B) The formula for Effective Atomic Number $(EAN)$ is:$EAN = Z - 	ext{Oxidation State} + 2 	imes 	ext{Coordination Number}$For $[Fe(CO)_5]$: $EAN = 26 - 0 + 2(5) = 36$For $[Cr(CN)_6]^{-3}$: $EAN = 24 - 3 + 2(6) = 33$For $[Mn_2(CO)_{10}]$: $EAN = 25 - 0 + 2(5) + 1 = 36$ (where $1$ is the contribution from the $Mn-Mn$ bond)For $[Fe(CN)_6]^{-4}$: $EAN = 26 - 2 + 2(6) = 36$Thus,$[Cr(CN)_6]^{-3}$ is the odd one out as its $EAN$ is $33$,while the others have an $EAN$ of $36$ (following the $EAN$ rule).

Select the odd one w.r.t. $EAN$ :-

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