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(D) In option $A$,the reaction of $sec$-butanol with $SOCl_2$ in the presence of pyridine proceeds via an $S_N2$ mechanism,resulting in the inversion

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(D) In option $A$,the reaction of $sec$-butanol with $SOCl_2$ in the presence of pyridine proceeds via an $S_N2$ mechanism,resulting in the inversion of configuration. The product shown is consistent with this.In option $B$,the reaction of $sec$-butanol with $PBr_3$ proceeds via an $S_N2$ mechanism,resulting in the inversion of configuration. The product shown is consistent with this.In option $C$,$NaH$ deprotonates the alcohol to form an alkoxide ion,which then performs an intramolecular $S_N2$ attack on the carbon bearing the bromine atom,forming a six-membered cyclic ether (tetrahydro-2H-pyran). This is correct.In option $D$,the reaction of benzene with $I-Cl$ in the presence of a Lewis acid like $AlCl_3$ is an electrophilic aromatic substitution. Since $I$ is less electronegative than $Cl$,$I^+$ acts as the electrophile. Therefore,the major product is iodobenzene,not chlorobenzene. Thus,this reaction does not represent the correct major product.

Select the reaction that does $NOT$ represent the correct major product.

Similar Questions

Why is $m$-dinitrobenzene obtained from $C_6H_5NO_2$?

The main product of the following reaction will be
$1$-fluoro-$2$-chloro-$4$-nitrobenzene + piperidine $\to$ Product

The rate of reaction is maximum if $G$ is:
$Cl-C_6H_4-G \xrightarrow{NaOH, \Delta/P} HO-C_6H_4-G$

Provide the following electrophilic substitution reactions of aryl halides:
$(i)$ Halogenation
$(ii)$ Nitration
$(iii)$ Sulphonation
$(iv)$ Friedel-Crafts reaction

The decreasing order of reactivity of $m$-nitrobromobenzene $(I)$,$2,4,6$-trinitrobromobenzene $(II)$,$p$-nitrobromobenzene $(III)$,and $2,4$-dinitrobromobenzene $(IV)$ towards $OH^{-}$ ions is

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