(C) The self-inductance $L$ of a long solenoid is given by the formula: $L = \frac{\mu_0 N^2 A}{l}$,where $\mu_0$ is the permeability of free space,$N

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Directly proportional to the area of cross-section

(C) The self-inductance $L$ of a long solenoid is given by the formula: $L = \frac{\mu_0 N^2 A}{l}$,where $\mu_0$ is the permeability of free space,$N$ is the total number of turns,$A$ is the cross-sectional area,and $l$ is the length of the solenoid.From this expression,it is clear that $L \propto A$. Therefore,the self-inductance is directly proportional to the area of the cross-section of the solenoid.

Class 12 Physics Electromagnetic Induction Self Induction

Easy

The self-inductance of a solenoid is:

A
Directly proportional to the current flowing through the coil
B
Directly proportional to its length
C
Directly proportional to the area of cross-section
D
Inversely proportional to the area of cross-section

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Electromagnetic Induction

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Self Induction

Current in a circuit falls from $5.0\, A$ to $0\, A$ in $0.1\, s$. If an average $emf$ of $200\, V$ is induced,estimate the self-inductance of the circuit in $H$.

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The current in a coil of inductance $0.2 \,H$ changes from $5 \,A$ to $2 \,A$ in $0.5 \,s$. The magnitude of the average induced emf in the coil is (in $\,V$)

MediumKCET 2020

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The current in an inductor of self-inductance $L=40 \text{ mH}$ is to be increased uniformly from $2 \text{ A}$ to $12 \text{ A}$ in $8 \text{ ms}$. The emf induced in the inductor during this process is (in $\text{ V}$)

MediumAP EAMCET 2021

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The self-inductance of a solenoid of length $31.4 \ cm$,area of cross-section $10^{-3} \ m^2$ having a total number of turns $500$ will be nearly $\left[\mu_0 = 4 \pi \times 10^{-7} \ SI \ unit\right]$.

DifficultMHT CET 2021

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$A$ varying current in a coil changes from $10 \,A$ to zero in $1.5 \,s$. If the average emf induced in the coil is $200 \,V$, the self-inductance of the coil is (in $\,H$)

EasyTS EAMCET 2020

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The self-inductance of a solenoid is:

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Current in a circuit falls from $5.0\, A$ to $0\, A$ in $0.1\, s$. If an average $emf$ of $200\, V$ is induced,estimate the self-inductance of the circuit in $H$.

The current in a coil of inductance $0.2 \,H$ changes from $5 \,A$ to $2 \,A$ in $0.5 \,s$. The magnitude of the average induced emf in the coil is (in $\,V$)

The current in an inductor of self-inductance $L=40 \text{ mH}$ is to be increased uniformly from $2 \text{ A}$ to $12 \text{ A}$ in $8 \text{ ms}$. The emf induced in the inductor during this process is (in $\text{ V}$)

The self-inductance of a solenoid of length $31.4 \ cm$,area of cross-section $10^{-3} \ m^2$ having a total number of turns $500$ will be nearly $\left[\mu_0 = 4 \pi \times 10^{-7} \ SI \ unit\right]$.

$A$ varying current in a coil changes from $10 \,A$ to zero in $1.5 \,s$. If the average emf induced in the coil is $200 \,V$, the self-inductance of the coil is (in $\,H$)

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