Show the distribution of electrons in an oxygen atom (atomic number $8$) using an orbital diagram.

(N/A) The electronic configuration of oxygen (atomic number $8$) is $1s^2 2s^2 2p^4$.
Following Hund's rule and the Pauli exclusion principle,the orbital diagram is:
$1s$: [↑↓]
$2s$: [↑↓]
$2p$: [↑↓] [↑] [↑]
From the orbital diagram,it is observed that there are two unpaired electrons in the $2p$ orbitals.