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(D) Silicon $(IV)$ chloride $(SiCl_4)$ undergoes hydrolysis to form silicic acid,which is $Si(OH)_4$ or $H_4SiO_4$.The chemical reaction is as follows

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$4$

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(D) Silicon $(IV)$ chloride $(SiCl_4)$ undergoes hydrolysis to form silicic acid,which is $Si(OH)_4$ or $H_4SiO_4$.The chemical reaction is as follows:$SiCl_4 + 4H_2O \rightarrow Si(OH)_4 + 4HCl$In the structure of silicic acid $(Si(OH)_4)$,the silicon atom is bonded to four $-OH$ groups.Therefore,the number of $-OH$ groups present in $X$ is $4$.

Silicon $(IV)$ chloride on hydrolysis gives an acid $X$. The number of $-OH$ groups present in $X$ is

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