(A) The reaction of silver benzoate with bromine in the presence of $CCl_4$ (Hunsdiecker reaction) leads to the formation of bromobenzene,carbon dioxi

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(A) The reaction of silver benzoate with bromine in the presence of $CCl_4$ (Hunsdiecker reaction) leads to the formation of bromobenzene,carbon dioxide,and silver bromide.$C_6H_5COOAg + Br_2 \xrightarrow{CCl_4} C_6H_5Br + CO_2 + AgBr$Therefore,the correct product is bromobenzene.