Silver chloride dissolves in excess of NH_4OH | vedclass

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Question

(B) Silver chloride $(AgCl)$ reacts with excess aqueous ammonia $(NH_4OH)$ to form a soluble complex salt,diamminesilver$(I)$ chloride.The chemical eq

Vedclass · Accepted Answer

$[Ag(NH_3)_2]^+$

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(B) Silver chloride $(AgCl)$ reacts with excess aqueous ammonia $(NH_4OH)$ to form a soluble complex salt,diamminesilver$(I)$ chloride.The chemical equation is: $AgCl(s) + 2NH_4OH(aq) 	o [Ag(NH_3)_2]Cl(aq) + 2H_2O(l)$.In the aqueous solution,this complex salt dissociates as follows: $[Ag(NH_3)_2]Cl(aq) 	o [Ag(NH_3)_2]^+(aq) + Cl^-(aq)$.Therefore,the cation present in the solution is $[Ag(NH_3)_2]^+$,which is the diamminesilver$(I)$ ion.

Silver chloride dissolves in excess of $NH_4OH$. The cation present in this solution is

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