Simplify the following switching circuit and | vedclass

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(A) The given circuit consists of two parallel blocks connected in series,which are then connected in parallel with a wire (which acts as an open circ

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$p \vee (q \wedge r)$

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(A) The given circuit consists of two parallel blocks connected in series,which are then connected in parallel with a wire (which acts as an open circuit or is not present in the simplified logic). Looking at the circuit: $1$. The first block has switches $p$ and $q$ in parallel,represented by $(p \vee q)$. $2$. The second block has switches $p$ and $r$ in parallel,represented by $(p \vee r)$. $3$. These two blocks are connected in series,so the expression is $(p \vee q) \wedge (p \vee r)$. Using the distributive law of Boolean algebra: $(p \vee q) \wedge (p \vee r) = p \vee (q \wedge r)$.

Simplify the following switching circuit and find the corresponding Boolean expression.

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