Simplify the following:sqrt[4]{81}-8 sqrt[3]{ | vedclass

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(A) To simplify the expression $\sqrt[4]{81}-8 \sqrt[3]{216}+15 \sqrt[5]{32}+\sqrt{225}$,we evaluate each radical term individually:$1$. $\sqrt[4]{81}

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(A) To simplify the expression $\sqrt[4]{81}-8 \sqrt[3]{216}+15 \sqrt[5]{32}+\sqrt{225}$,we evaluate each radical term individually:$1$. $\sqrt[4]{81} = \sqrt[4]{3^{4}} = 3$$2$. $\sqrt[3]{216} = \sqrt[3]{6^{3}} = 6$,so $8 \sqrt[3]{216} = 8 	imes 6 = 48$$3$. $\sqrt[5]{32} = \sqrt[5]{2^{5}} = 2$,so $15 \sqrt[5]{32} = 15 	imes 2 = 30$$4$. $\sqrt{225} = \sqrt{15^{2}} = 15$Substituting these values back into the original expression:$3 - 48 + 30 + 15$$= (3 + 30 + 15) - 48$$= 48 - 48 = 0$

Simplify the following:
$\sqrt[4]{81}-8 \sqrt[3]{216}+15 \sqrt[5]{32}+\sqrt{225}$

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Simplify the following:$\sqrt[4]{81}-8 \sqrt[3]{216}+15 \sqrt[5]{32}+\sqrt{225}$