Six wooden cubes of length 3 , cm are arrange | vedclass

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Question

(A) cuboid is formed by arranging six cubes touching each other face to face in a row.For the cuboid so formed,the length $l = 6 	imes 3 \, cm = 18 \

Vedclass · Accepted Answer

$234$

Vedclass · Answer

(A) cuboid is formed by arranging six cubes touching each other face to face in a row.For the cuboid so formed,the length $l = 6 	imes 3 \, cm = 18 \, cm$.The breadth $b = 3 \, cm$ and the height $h = 3 \, cm$.The total surface area $(TSA)$ of the cuboid is given by the formula $2(lb + bh + hl)$.Substituting the values: $TSA = 2(18 	imes 3 + 3 	imes 3 + 3 	imes 18)$.$TSA = 2(54 + 9 + 54) = 2(117) = 234 \, cm^2$.Thus,the total surface area of the solid formed is $234 \, cm^2$.

Six wooden cubes of length $3 \, cm$ are arranged in a row touching each other face to face. Find the total surface area of the solid formed in this manner. (in $cm^2$)

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