Sodium borate on reaction with $H_2SO_4$ (conc.) and $C_2H_5OH$ gives a compound '$A$' which burns with a green flame. The compound '$A$' is

  • A
    $H_2B_4O_7$
  • B
    $(C_2H_5)_2B_4O_7$
  • C
    $H_3BO_3$
  • D
    $(C_2H_5)_3BO_3$

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