Sodium Carbonate cannot be used in place of ( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the analysis of group $V$ cations,$(NH_4)_2CO_3$ is used as a group reagent in the presence of $NH_4Cl$ and $NH_4OH$.$NH_4Cl$ suppresses the io

Vedclass · Accepted Answer

$Mg^{2+}$ ions will also be precipitated

Vedclass · Answer

(A) In the analysis of group $V$ cations,$(NH_4)_2CO_3$ is used as a group reagent in the presence of $NH_4Cl$ and $NH_4OH$.$NH_4Cl$ suppresses the ionization of $(NH_4)_2CO_3$ due to the common ion effect,keeping the concentration of $CO_3^{2-}$ low enough to exceed only the solubility product $(K_{sp})$ of $Ca^{2+}$,$Ba^{2+}$,and $Sr^{2+}$ carbonates.If $Na_2CO_3$ is used instead,it is a strong electrolyte and dissociates completely to provide a high concentration of $CO_3^{2-}$ ions.This high concentration of $CO_3^{2-}$ exceeds the $K_{sp}$ of $MgCO_3$ as well,causing $Mg^{2+}$ ions to precipitate along with the group $V$ cations.

Sodium Carbonate cannot be used in place of $(NH_4)_2CO_3$ for the identification of $Ca^{2+}$,$Ba^{2+}$,and $Sr^{2+}$ ions (in group $V$) during mixture analysis because

Similar Questions

The incorrect statement out of the following is:

Assign $A, B, C, D$ from the given type of reaction.
$FeCl_3 + NH_3 \text{ (excess)} \longrightarrow Fe(OH)_3 \downarrow$

Which of the following ions gives a white precipitate when $HCl$ is added to its aqueous solution?

In the group $III$ radicals,in place of $NH_4Cl$,which of the following can be used?

The cation that will not be precipitated by $H_2S$ in the presence of $dil. \ HCl$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module