Sodium has a body-centered cubic (BCC) packin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a body-centered cubic $(BCC)$ structure,the nearest neighbor distance $d$ is given by the distance between the corner atom and the body-center

Vedclass · Accepted Answer

$4.3$

Vedclass · Answer

(B) For a body-centered cubic $(BCC)$ structure,the nearest neighbor distance $d$ is given by the distance between the corner atom and the body-centered atom.In a $BCC$ unit cell with lattice parameter $a$,the body diagonal is $\sqrt{3}a$.The distance between the nearest atoms is $d = \frac{\sqrt{3}a}{2}$.Given $d = 3.7 \mathring{A}$,we can solve for $a$:$a = \frac{2d}{\sqrt{3}} = \frac{2 	imes 3.7}{1.732} \approx 4.27 \mathring{A}$.Rounding to one decimal place,we get $a = 4.3 \mathring{A}$.

Sodium has a body-centered cubic $(BCC)$ packing. If the distance between two nearest atoms is $3.7 \mathring{A}$,then its lattice parameter is.....$\mathring{A}$

Similar Questions

What is the band gap energy for an insulator in $eV$?

In a semiconducting material,the mobilities of electrons and holes are $\mu_e$ and $\mu_h$ respectively. Which of the following is true?

Electrical conductivity of a semiconductor:

The resistance of a semiconductor at $0 \ K$ is:

Carbon,Silicon,and Germanium atoms have four valence electrons each. Their valence and conduction bands are separated by energy band gaps represented by $(E_g)_C$,$(E_g)_{Si}$,and $(E_g)_{Ge}$ respectively. Which one of the following relationships is true in their case?

Vedclass Test Series

Exam Paper Generator

Online Exam Module