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(B) According to Wien's displacement law,the product of the wavelength of maximum intensity $(\lambda_m)$ and the absolute temperature $(T)$ of a blac

Vedclass · Accepted Answer

$9600$

Vedclass · Answer

(B) According to Wien's displacement law,the product of the wavelength of maximum intensity $(\lambda_m)$ and the absolute temperature $(T)$ of a black body is constant.$\lambda_{m1} T_1 = \lambda_{m2} T_2$Given:$T_1 = 6000\, K$$\lambda_{m1} = 4800\, \mathring{A}$$T_2 = 3000\, K$Substituting the values into the equation:$4800 	imes 6000 = \lambda_{m2} 	imes 3000$$\lambda_{m2} = \frac{4800 	imes 6000}{3000}$$\lambda_{m2} = 4800 	imes 2 = 9600\, \mathring{A}$Therefore,the peak intensity would occur at a wavelength of $9600\, \mathring{A}$.

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