(B) According to Wien's displacement law,the product of the wavelength of maximum intensity $(\lambda_m)$ and the absolute temperature $(T)$ is a cons

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(B) According to Wien's displacement law,the product of the wavelength of maximum intensity $(\lambda_m)$ and the absolute temperature $(T)$ is a constant:$\lambda_m T = b$ (constant)Given:Initial temperature $T_1 = 6000\,K$Initial peak wavelength $\lambda_{m1} = 4800\,\mathring{A}$Final temperature $T_2 = 3000\,K$Using the relation $\lambda_{m1} T_1 = \lambda_{m2} T_2$:$4800 \times 6000 = \lambda_{m2} \times 3000$Solving for $\lambda_{m2}$:$\lambda_{m2} = \frac{4800 \times 6000}{3000}$$\lambda_{m2} = 4800 \times 2$$\lambda_{m2} = 9600\,\mathring{A}$

Class 11 Physics 10-2.Heat Transfer Spectral Emissive Power and Wien's Displacement Law

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Solar radiation emitted by the sun resembles that emitted by a black body at a temperature of $6000\,K$. Maximum intensity is emitted at a wavelength of about $4800\,\mathring{A}$. If the sun was cooled down from $6000\,K$ to $3000\,K$,then the peak intensity would occur at a wavelength of ........ $\mathring{A}$.

A
$4800$
B
$9600$
C
$2400$
D
$19200$

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10-2.Heat Transfer

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Spectral Emissive Power and Wien's Displacement Law

$A$ black body emits radiations of maximum intensity at a wavelength of $5000 \mathring A$,when the temperature of the body is $1227^{\circ}C$. If the temperature of the body is increased by $1000^{\circ}C$,the maximum intensity of emitted radiation would be observed at..... $\mathring A$.

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The colour of a shining bright star is an indication of its

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$Assertion :$ For higher temperature, the peak emission wavelength of a blackbody shifts to lower wavelengths.
$Reason :$ Peak emission wavelength of a blackbody is proportional to the fourth power of temperature.

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The wavelength corresponding to the maximum energy emitted by a body at a certain temperature is ${\lambda _0}$. If the temperature of the body is increased such that the new maximum wavelength becomes $\frac{3{\lambda _0}}{4}$, then by what factor does the emissive power increase?

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On investigation of light from three different stars $A, B$ and $C$, it was found that in the spectrum of $A$ the intensity of red colour is maximum, in $B$ the intensity of blue colour is maximum and in $C$ the intensity of yellow colour is maximum. From these observations, it can be concluded that

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$A$ black body emits radiations of maximum intensity at a wavelength of $5000 \mathring A$,when the temperature of the body is $1227^{\circ}C$. If the temperature of the body is increased by $1000^{\circ}C$,the maximum intensity of emitted radiation would be observed at..... $\mathring A$.

The colour of a shining bright star is an indication of its

$Assertion :$ For higher temperature, the peak emission wavelength of a blackbody shifts to lower wavelengths.$Reason :$ Peak emission wavelength of a blackbody is proportional to the fourth power of temperature.

The wavelength corresponding to the maximum energy emitted by a body at a certain temperature is ${\lambda _0}$. If the temperature of the body is increased such that the new maximum wavelength becomes $\frac{3{\lambda _0}}{4}$, then by what factor does the emissive power increase?

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$Assertion :$ For higher temperature, the peak emission wavelength of a blackbody shifts to lower wavelengths.
$Reason :$ Peak emission wavelength of a blackbody is proportional to the fourth power of temperature.