Solubility of CaF_2 in a solution of Ca(NO_3) | vedclass

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(D) The dissolution of $CaF_2$ is given by: $CaF_2(s) \rightleftharpoons Ca^{2+}(aq) + 2F^{-}(aq)$.Let $s$ be the solubility of $CaF_2$ in the presenc

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$\frac{1}{2}[F^{-}]$

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(D) The dissolution of $CaF_2$ is given by: $CaF_2(s) \rightleftharpoons Ca^{2+}(aq) + 2F^{-}(aq)$.Let $s$ be the solubility of $CaF_2$ in the presence of $Ca(NO_3)_2$.From the stoichiometry of the reaction,for every $1 \ mol$ of $CaF_2$ that dissolves,$2 \ mol$ of $F^{-}$ ions are produced.Therefore,the concentration of fluoride ions in the solution is $[F^{-}] = 2s$.Rearranging this for solubility $s$,we get $s = \frac{1}{2}[F^{-}]$.

Solubility of $CaF_2$ in a solution of $Ca(NO_3)_2$ will be represented by the concentration term?

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