Solubility product constant (K_{sp}) of salts | vedclass

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(D) For $MX$: $K_{sp} = s^2 \implies s = \sqrt{4.0 	imes 10^{-8}} = 2.0 	imes 10^{-4} 	ext{ mol } dm^{-3}$.For $MX_2$: $K_{sp} = 4s^3 \implies s =

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$MX > M_3X > MX_2$

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(D) For $MX$: $K_{sp} = s^2 \implies s = \sqrt{4.0 	imes 10^{-8}} = 2.0 	imes 10^{-4} 	ext{ mol } dm^{-3}$.For $MX_2$: $K_{sp} = 4s^3 \implies s = \sqrt[3]{(3.2 	imes 10^{-14}) / 4} = \sqrt[3]{8.0 	imes 10^{-15}} = 2.0 	imes 10^{-5} 	ext{ mol } dm^{-3}$.For $M_3X$: $K_{sp} = 27s^4 \implies s = \sqrt[4]{(2.7 	imes 10^{-15}) / 27} = \sqrt[4]{1.0 	imes 10^{-16}} = 1.0 	imes 10^{-4} 	ext{ mol } dm^{-3}$.Comparing the values: $2.0 	imes 10^{-4} > 1.0 	imes 10^{-4} > 2.0 	imes 10^{-5}$.Therefore,the order of solubility is $MX > M_3X > MX_2$.

Solubility product constant $(K_{sp})$ of salts of types $MX$,$MX_2$ and $M_3X$ at temperature '$T$' are $4.0 \times 10^{-8}$,$3.2 \times 10^{-14}$ and $2.7 \times 10^{-15}$,respectively. Solubilities $(\text{mol } dm^{-3})$ of the salts at temperature '$T$' are in the order:

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