Solve $-5 \leq \frac{5-3x}{2} \leq 8$.

(N/A) Given the inequality: $-5 \leq \frac{5-3x}{2} \leq 8$
Multiply all parts by $2$:
$-10 \leq 5-3x \leq 16$
Subtract $5$ from all parts:
$-15 \leq -3x \leq 11$
Divide by $-3$ (note that the inequality signs reverse when dividing by a negative number):
$5 \geq x \geq -\frac{11}{3}$
Rearranging the inequality,we get:
$-\frac{11}{3} \leq x \leq 5$