Solve the following inequality: $\frac{2x+3}{5} - 2 < \frac{3(x-2)}{5}$

Solve the given inequality for real $x$: $\frac{x}{3} > \frac{x}{2} + 1$

The solution set of $|x-1| + |x+1| < 2$ is...

The largest interval containing $x$ for which $x^{12}-x^9+x^4-x+1 > 0$ is

Let $a, b, c, d$ be numbers in the set $\{1, 2, 3, 4, 5, 6\}$ such that the curves $y = 2x^3 + ax + b$ and $y = 2x^3 + cx + d$ have no point in common. The maximum possible value of $(a - c)^2 + b - d$ is

Write the following as intervals: $\{ x:x \in R, -12 < x < -10 \}$