Solve the following pair of linear equations | vedclass

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(C) Given equations are:$(1) \quad 4x - 3y = 8$$(2) \quad 6x - y = \frac{29}{3}$To eliminate $y$,multiply equation $(2)$ by $3$:$18x - 3y = 29 \quad (

Vedclass · Accepted Answer

$(\frac{3}{2}, -\frac{2}{3})$

Vedclass · Answer

(C) Given equations are:$(1) \quad 4x - 3y = 8$$(2) \quad 6x - y = \frac{29}{3}$To eliminate $y$,multiply equation $(2)$ by $3$:$18x - 3y = 29 \quad (3)$Subtract equation $(1)$ from equation $(3)$:$(18x - 3y) - (4x - 3y) = 29 - 8$$14x = 21$$x = \frac{21}{14} = \frac{3}{2}$Substitute $x = \frac{3}{2}$ into equation $(2)$:$6(\frac{3}{2}) - y = \frac{29}{3}$$9 - y = \frac{29}{3}$$y = 9 - \frac{29}{3} = \frac{27 - 29}{3} = -\frac{2}{3}$Thus,the solution is $(x, y) = (\frac{3}{2}, -\frac{2}{3})$.

Solve the following pair of linear equations by the method of elimination:
$4x - 3y = 8$
$6x - y = \frac{29}{3}$

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Solve the following pair of linear equations by the method of elimination:$4x - 3y = 8$$6x - y = \frac{29}{3}$