Solve the following pair of equations by the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given equations are:$(1)$ $x + 2y = \frac{3}{2}$$(2)$ $2x + y = \frac{3}{2}$To eliminate $y$,multiply equation $(1)$ by $1$ and equation $(2)$ by

Vedclass · Accepted Answer

$\left(\frac{1}{2}, \frac{1}{2}\right)$

Vedclass · Answer

(A) Given equations are:$(1)$ $x + 2y = \frac{3}{2}$$(2)$ $2x + y = \frac{3}{2}$To eliminate $y$,multiply equation $(1)$ by $1$ and equation $(2)$ by $2$:$x + 2y = \frac{3}{2}$$4x + 2y = 3$Subtracting the first equation from the second:$(4x - x) + (2y - 2y) = 3 - \frac{3}{2}$$3x = \frac{6 - 3}{2} = \frac{3}{2}$$x = \frac{3}{2 	imes 3} = \frac{1}{2}$Substitute $x = \frac{1}{2}$ into equation $(1)$:$\frac{1}{2} + 2y = \frac{3}{2}$$2y = \frac{3}{2} - \frac{1}{2} = \frac{2}{2} = 1$$y = \frac{1}{2}$Thus,the solution is $\left(\frac{1}{2}, \frac{1}{2}ight)$.

Solve the following pair of equations by the method of elimination:
$x + 2y = \frac{3}{2}$
$2x + y = \frac{3}{2}$

Similar Questions

$A$ pair of linear equations which has a unique solution $x=2, y=-3$ is

Solve the following pair of equations: $2x + y = \frac{7xy}{3}, x + 3y = \frac{11xy}{3}$

The line represented by $x=7$ is parallel to the $x$-axis. Justify whether the statement is true or not.

$A$ fraction becomes $\frac{4}{5}$ if $1$ is added to both the numerator and the denominator. If $5$ is subtracted from both the numerator and the denominator,it becomes $\frac{1}{2}$. Find the fraction.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Solve the following pair of equations by the method of elimination:$x + 2y = \frac{3}{2}$$2x + y = \frac{3}{2}$