Solve the following system of inequalities graphically: $3x + 2y \leq 12, x \geq 1, y \geq 2$

(N/A) $3x + 2y \leq 12$ ...... $(1)$
$x \geq 1$ ...... $(2)$
$y \geq 2$ ...... $(3)$
The graphs of the lines $3x + 2y = 12$,$x = 1$,and $y = 2$ are drawn in the figure below.
Inequality $(1)$ represents the region below the line $3x + 2y = 12$ (including the line $3x + 2y = 12$).
Inequality $(2)$ represents the region on the right side of the line $x = 1$ (including the line $x = 1$).
Inequality $(3)$ represents the region above the line $y = 2$ (including the line $y = 2$).
Hence,the solution of the given system of linear inequalities is represented by the common shaded region including the points on the respective lines.