Solve the given inequality for real $x: 3(x-1) \leq 2(x-3)$

The solution set of $|x-1|+|x-2| < 3$ is

The solution of the inequality $3(x-1) \leq 2(x-3)$ is

The set $A = \{x : |2x + 3| < 7\}$ is equal to which of the following sets?

Let $a, b, c, d$ be numbers in the set $\{1, 2, 3, 4, 5, 6\}$ such that the curves $y = 2x^3 + ax + b$ and $y = 2x^3 + cx + d$ have no point in common. The maximum possible value of $(a - c)^2 + b - d$ is

Solve $24x < 100$,when $x$ is an integer.