Solve the given inequality for real x: 37-(3x | vedclass

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(A) Given inequality: $37-(3x+5) \geq 9x-8(x-3)$Step $1$: Simplify both sides of the inequality.$37-3x-5 \geq 9x-8x+24$$32-3x \geq x+24$Step $2$: Coll

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$(-\infty, 2]$

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(A) Given inequality: $37-(3x+5) \geq 9x-8(x-3)$Step $1$: Simplify both sides of the inequality.$37-3x-5 \geq 9x-8x+24$$32-3x \geq x+24$Step $2$: Collect the terms involving $x$ on one side and constants on the other.$32-24 \geq x+3x$$8 \geq 4x$Step $3$: Divide by $4$.$2 \geq x$ or $x \leq 2$Thus,all real numbers $x$ which are less than or equal to $2$ are the solutions.Hence,the solution set is $(-\infty, 2]$.

Solve the given inequality for real $x$: $37-(3x+5) \geq 9x-8(x-3)$

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