Solve the given two equations and select the correct answer from the given options.
$I.$ $x = \sqrt{2304}$
$II.$ $y^2 = 2304$

  • A
    if $x > y$
  • B
    if $x < y$
  • C
    if $x \ge y$
  • D
    if $x \le y$

Explore More

Similar Questions

If the product of the roots of the equation $mx^2 + 6x + (2m - 1) = 0$ is $-1$,then the value of $m$ will be:

The value of $p$ for which one root of the equation ${x^2} - 30x + p = 0$ is the square of the other,are

If the roots of the quadratic equation $\frac{x - m}{mx + 1} = \frac{x + n}{nx + 1}$ are reciprocal to each other,then

The solution set of the equation $x^{\log_x(1 - x)^2} = 9$ is

An equation equivalent to the quadratic equation $x^{2}-6x+5=0$ is:

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo