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(B) Given equations are:$I.$ $12x + 3y = 14$$II.$ $4x + 2y = 16$To eliminate $x$,multiply equation $II$ by $3$:$3 	imes (4x + 2y) = 3 	imes 16$$12x

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if $x < y$

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(B) Given equations are:$I.$ $12x + 3y = 14$$II.$ $4x + 2y = 16$To eliminate $x$,multiply equation $II$ by $3$:$3 	imes (4x + 2y) = 3 	imes 16$$12x + 6y = 48$ (Equation $III$)Subtract equation $I$ from equation $III$:$(12x + 6y) - (12x + 3y) = 48 - 14$$3y = 34$$y = \frac{34}{3} \approx 11.33$Substitute $y = \frac{34}{3}$ into equation $II$:$4x + 2(\frac{34}{3}) = 16$$4x + \frac{68}{3} = 16$$4x = 16 - \frac{68}{3}$$4x = \frac{48 - 68}{3} = -\frac{20}{3}$$x = -\frac{5}{3} \approx -1.67$Comparing the values,$x = -1.67$ and $y = 11.33$.Since $-1.67 < 11.33$,therefore $x < y$.

Solve the given two equations and select the correct answer from the given options.
$I.$ $12x + 3y = 14$
$II.$ $4x + 2y = 16$

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Solve the given two equations and select the correct answer from the given options.$I.$ $12x + 3y = 14$$II.$ $4x + 2y = 16$