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(D) $I.$ For $391 x^{2} + 1344 x + 1073 = 0$:Using the quadratic formula or factorization,we find the roots.$391 = 17 	imes 23$ and $1073 = 29 	imes

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if $x = y$ or relationship between $x$ and $y$ cannot be established.

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(D) $I.$ For $391 x^{2} + 1344 x + 1073 = 0$:Using the quadratic formula or factorization,we find the roots.$391 = 17 	imes 23$ and $1073 = 29 	imes 37$.Splitting the middle term: $493 + 851 = 1344$.$391 x^{2} + 493 x + 851 x + 1073 = 0$$17x(23x + 29) + 37(23x + 29) = 0$$(17x + 37)(23x + 29) = 0$$x = -\frac{37}{17} \approx -2.176$ and $x = -\frac{29}{23} \approx -1.261$.$II.$ For $437 y^{2} + 1074 y + 589 = 0$:$437 = 19 	imes 23$ and $589 = 19 	imes 31$.Splitting the middle term: $361 + 713 = 1074$.$437 y^{2} + 361 y + 713 y + 589 = 0$$19y(23y + 19) + 31(23y + 19) = 0$$(19y + 31)(23y + 19) = 0$$y = -\frac{31}{19} \approx -1.631$ and $y = -\frac{19}{23} \approx -0.826$.Comparing the values:$x_1 = -2.176, x_2 = -1.261$$y_1 = -1.631, y_2 = -0.826$Since $x_1  y_1$,the relationship cannot be established.

Solve the given two equations and provide the correct answer from the given options.
$I.$ $391 x^{2} + 1344 x + 1073 = 0$
$II.$ $437 y^{2} + 1074 y + 589 = 0$

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Solve the given two equations and provide the correct answer from the given options.$I.$ $391 x^{2} + 1344 x + 1073 = 0$$II.$ $437 y^{2} + 1074 y + 589 = 0$