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(A) Given equations are:$5x + 4y = 41$ ... $(i)$$4x + 5y = 40$ ... (ii)To solve,multiply equation $(i)$ by $5$ and equation (ii) by $4$:$25x + 20y = 2

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if $x > y$

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(A) Given equations are:$5x + 4y = 41$ ... $(i)$$4x + 5y = 40$ ... (ii)To solve,multiply equation $(i)$ by $5$ and equation (ii) by $4$:$25x + 20y = 205$ ... (iii)$16x + 20y = 160$ ... (iv)Subtracting equation (iv) from equation (iii):$(25x - 16x) + (20y - 20y) = 205 - 160$$9x = 45$$x = 5$Substitute $x = 5$ into equation $(i)$:$5(5) + 4y = 41$$25 + 4y = 41$$4y = 16$$y = 4$Since $x = 5$ and $y = 4$,we have $x > y$.

Solve the given two equations and select the correct answer from the given options.
$I.$ $\sqrt{25} x + \sqrt{16} y = 41$
$II.$ $\sqrt{16} x + \sqrt{25} y = 40$

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Solve the given two equations and select the correct answer from the given options.$I.$ $\sqrt{25} x + \sqrt{16} y = 41$$II.$ $\sqrt{16} x + \sqrt{25} y = 40$