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(A) Given equations are:$I. 7x + 3y = 77$$II. 2x + 5y = \sqrt{2601} = 51$To solve the system,multiply equation $I$ by $2$ and equation $II$ by $7$:$14

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if $x > y$

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(A) Given equations are:$I. 7x + 3y = 77$$II. 2x + 5y = \sqrt{2601} = 51$To solve the system,multiply equation $I$ by $2$ and equation $II$ by $7$:$14x + 6y = 154$$14x + 35y = 357$Subtract the first resulting equation from the second:$(14x + 35y) - (14x + 6y) = 357 - 154$$29y = 203$$y = 203 / 29 = 7$Substitute $y = 7$ into equation $II$:$2x + 5(7) = 51$$2x + 35 = 51$$2x = 16$$x = 8$Comparing the values,$x = 8$ and $y = 7$,so $x > y$.

Solve the given two equations and select the correct answer from the given options.
$I.$ $7x + 3y = 77$
$II.$ $2x + 5y = (2601)^{1/2}$

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Solve the given two equations and select the correct answer from the given options.$I.$ $7x + 3y = 77$$II.$ $2x + 5y = (2601)^{1/2}$