Solve the given two equations and select the correct option.
$I.$ $\sqrt{500} x + \sqrt{402} = 0$
$II.$ $\sqrt{360} y + \sqrt{200} = 0$

  • A
    $x > y$
  • B
    $x \geq y$
  • C
    $x < y$
  • D
    $x \leq y$

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