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(A) Step $1$: Solve equation $I$.$\sqrt{1225} x + \sqrt{4900} = 0$$35 x + 70 = 0$$35 x = -70$$x = \frac{-70}{35} = -2$Step $2$: Solve equation $II$.$(

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if $x > y$

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(A) Step $1$: Solve equation $I$.$\sqrt{1225} x + \sqrt{4900} = 0$$35 x + 70 = 0$$35 x = -70$$x = \frac{-70}{35} = -2$Step $2$: Solve equation $II$.$(81)^{1/4} y + (343)^{1/3} = 0$Since $81 = 3^4$ and $343 = 7^3$,we have:$(3^4)^{1/4} y + (7^3)^{1/3} = 0$$3 y + 7 = 0$$3 y = -7$$y = -\frac{7}{3} \approx -2.33$Step $3$: Compare $x$ and $y$.$x = -2$$y \approx -2.33$Since $-2 > -2.33$,therefore $x > y$.

Solve the given two equations and select the correct answer from the given options:
$I.$ $\sqrt{1225} x + \sqrt{4900} = 0$
$II.$ $(81)^{1/4} y + (343)^{1/3} = 0$

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Solve the given two equations and select the correct answer from the given options:$I.$ $\sqrt{1225} x + \sqrt{4900} = 0$$II.$ $(81)^{1/4} y + (343)^{1/3} = 0$