Some magnetic flux is changed through a coil | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The induced charge $q$ flowing through a circuit is given by the relation $q = \frac{\Delta \phi}{R}$,where $\Delta \phi$ is the change in magneti

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(A) The induced charge $q$ flowing through a circuit is given by the relation $q = \frac{\Delta \phi}{R}$,where $\Delta \phi$ is the change in magnetic flux and $R$ is the resistance of the coil.Rearranging the formula,we get the change in flux: $\Delta \phi = q 	imes R$.The charge $q$ is equal to the area under the current-time $(I-t)$ graph.Given the graph is a triangle with base $b = 0.1 \, s$ and height $h = 4 \, A$,the area $q = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes 0.1 	imes 4 = 0.2 \, C$.Substituting the values into the flux equation: $\Delta \phi = 0.2 \, C 	imes 10 \, \Omega = 2 \, Wb$.

Similar Questions

When a conducting wire $XY$ is moved towards the right,a current flows in the anti-clockwise direction in the loop. The direction of the magnetic field at point $O$ is

$A$ loop of irregular shape of conducting wire (as shown in the figure) is placed in a uniform magnetic field perpendicular to the plane of the paper. If the loop changes into a circular shape,the direction of the induced current will be:

Two identical circular loops of metal wire are lying on a table without touching each other. $Loop-A$ carries a current which increases with time. In response,the $loop-B$

Whenever a magnet is moved towards or away from a conducting coil,and an e.m.f. is induced,the magnitude of which is independent of:

$A$ coil of $n$ turns and resistance $R \text{ } \Omega$ is connected in series with a resistance $R/4$. The combination is moved for time $t$ second through flux $\phi_1$ to $\phi_2$. The induced current in the circuit is

Vedclass Test Series

Exam Paper Generator

Online Exam Module