Sonu invested 10 % more than Mona. Mona inves | vedclass

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(B) Let the amount invested by Raghu be $₹ x$.Since Mona invested $10 \%$ less than Raghu,the amount invested by Mona is $x - 0.10x = 0.9x$.Since Sonu

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$2,000$

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(B) Let the amount invested by Raghu be $₹ x$.Since Mona invested $10 \%$ less than Raghu,the amount invested by Mona is $x - 0.10x = 0.9x$.Since Sonu invested $10 \%$ more than Mona,the amount invested by Sonu is $0.9x + 0.10(0.9x) = 0.9x + 0.09x = 0.99x$.The total sum of their investments is given as $₹ 5,780$.Therefore,$x + 0.9x + 0.99x = 5,780$.$2.89x = 5,780$.$x = \frac{5,780}{2.89} = 2,000$.Thus,Raghu invested $₹ 2,000$.

Sonu invested $10 \%$ more than Mona. Mona invested $10 \%$ less than Raghu. If the total sum of their investments is ₹$5,780$,how much amount did Raghu invest?

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