Standing waves are produced in a 10 ; m long | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The length of the string is $l = 10 \; m$. The number of segments is $p = 5$. The wave velocity is $v = 20 \; m/s$.For a string vibrating in $p$ s

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(C) The length of the string is $l = 10 \; m$. The number of segments is $p = 5$. The wave velocity is $v = 20 \; m/s$.For a string vibrating in $p$ segments,the length $l$ is related to the wavelength $\lambda$ by the formula $l = p \cdot \frac{\lambda}{2}$.Substituting the values,we get $10 = 5 \cdot \frac{\lambda}{2}$,which simplifies to $\lambda = \frac{10 \cdot 2}{5} = 4 \; m$.The frequency $f$ is given by the relation $f = \frac{v}{\lambda}$.Substituting the values,$f = \frac{20 \; m/s}{4 \; m} = 5 \; Hz$.

Standing waves are produced in a $10 \; m$ long stretched string. If the string vibrates in $5$ segments and the wave velocity is $20 \; m/s$,the frequency is ... $Hz$.

Similar Questions

$A$ standing wave with a number of loops is produced on a string fixed at both ends. Which one of the following statements is correct?

At a certain instant,a stationary transverse wave is found to have maximum kinetic energy. The appearance of the string at that instant is:

Spacing between two successive nodes in a standing wave on a string is $x$. If the frequency of the standing wave is kept unchanged but the tension in the string is doubled,then the new spacing between successive nodes will become

What are nodes and antinodes?

Two sinusoidal waves with same wavelengths and amplitudes travel in opposite directions along a string with a speed $10 \, ms^{-1}$. If the minimum time interval between two instants when the string is flat is $0.5 \, s$,the wavelength of the waves is .... $m$

Vedclass Test Series

Exam Paper Generator

Online Exam Module