Statement I : SO_2 and H_2O both possess V-sh | vedclass

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(C) $1$. $SO_2$ has $sp^2$ hybridization with one lone pair on $S$,resulting in a $V$-shaped (bent) geometry with a bond angle of approximately $119^{

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Statement $I$ is correct but Statement $II$ is incorrect

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(C) $1$. $SO_2$ has $sp^2$ hybridization with one lone pair on $S$,resulting in a $V$-shaped (bent) geometry with a bond angle of approximately $119^{\circ}$.$2$. $H_2O$ has $sp^3$ hybridization with two lone pairs on $O$,resulting in a $V$-shaped (bent) geometry with a bond angle of approximately $104.5^{\circ}$.$3$. Both molecules possess a $V$-shaped structure,so Statement $I$ is correct.$4$. Comparing the bond angles,$119^{\circ} > 104.5^{\circ}$,so the bond angle of $SO_2$ is greater than that of $H_2O$. Thus,Statement $II$ is incorrect.

Statement $I$ : $SO_2$ and $H_2O$ both possess $V$-shaped structure.
Statement $II$ : The bond angle of $SO_2$ is less than that of $H_2O$.
In the light of the above statements,choose the most appropriate answer from the options given below:

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Statement $I$ : $SO_2$ and $H_2O$ both possess $V$-shaped structure.Statement $II$ : The bond angle of $SO_2$ is less than that of $H_2O$.In the light of the above statements,choose the most appropriate answer from the options given below: