Statement $1$: $[Ti(H_2O)_6]^{4+}$ is coloured while $[Sc(H_2O)_6]^{3+}$ is colourless.
Statement $2$: $d-d$ transition is not possible in $[Sc(H_2O)_6]^{3+}$.

  • A
    Statement-$1$ is True,Statement-$2$ is True; Statement-$2$ is a correct explanation for Statement-$1$.
  • B
    Statement-$1$ is True,Statement-$2$ is True; Statement-$2$ is $NOT$ a correct explanation for Statement-$1$.
  • C
    Statement-$1$ is True,Statement-$2$ is False.
  • D
    Statement-$1$ is False,Statement-$2$ is True.

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Match the correct option.
$A$. $[CoF_6]^{3-}$$M$. $sp^3d^2$,paramagnetic
$B$. $[Mn(CN)_6]^{3-}$$N$. $sp^3d^2$,diamagnetic
$C$. $[Co(C_2O_4)_3]^{3-}$$O$. $d^2sp^3$,paramagnetic
$D$. $[Zn(H_2O)_6]^{2+}$$P$. $d^2sp^3$,diamagnetic

$A$ list of species having the formula $XZ_4$ is given below.
$XeF_4, SF_4, SiF_4, BF_4^-, BrF_4^-, [Cu(NH_3)_4]^{2+}, [FeCl_4]^{2-}, [CoCl_4]^{2-}$ and $[PtCl_4]^{2-}$.
Defining shape on the basis of the location of $X$ and $Z$ atoms,the total number of species having a square planar shape is

What is the color of the complex $[Co(H_2O)_6]Cl_3$?

The hybridization of $Fe$ in $K_3[Fe(CN)_6]$ is

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Which of the following complexes exhibits outer orbital hybridization?

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