The structural formula for Lewisite is:

  • A
    $CHCl=CH-AsCl_3$
  • B
    $CHCl=CH-AsCl$
  • C
    $CHCl=CH-AsCl_2$
  • D
    $CH_2=CH-AsCl_2$

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Similar Questions

The general formula for alkyl halides is

Match the type of halide given in Column-$(I)$ with the structures in Column-$(II)$.
Column-$(I)$ (Structure)Column-$(II)$ (Type)
$(A)$ $C_6H_5CH_2X$$(i)$ $4^{\circ}$ Benzylic halide
$(B)$ $C_6H_5CH(CH_3)X$$(ii)$ $3^{\circ}$ Benzylic halide
$(C)$ $C_6H_5C(CH_3)_2X$$(iii)$ $2^{\circ}$ Benzylic halide
$(D)$ $C_6H_5X$$(iv)$ $1^{\circ}$ Benzylic halide
$(v)$ Aryl halide

Give the $IUPAC$ names of the following compounds:
$(i)$ $CH_3-CH(Cl)-CH(Br)-CH_3$
$(ii)$ $CHF_2-CBrClF$
$(iii)$ $Cl-CH_2-C\equiv C-CH_2-Br$
$(iv)$ $(CCl_3)_3-C-Cl$
$(v)$ $CH_3-C(p-ClC_6H_4)_2-CH(Br)-CH_3$
$(vi)$ $(CH_3)_3-C-CH=CCl-C_6H_4I-p$

In which of the following compounds is the carbon atom bonded to the halogen $NOT$ $sp^3$ hybridized?

Column-$(I)$ contains the formula of an alkyl halide and Column-$(II)$ contains its type. Match Column-$(I)$ with Column-$(II)$.
Column-$(I)$ Column-$(II)$
$(A)$ $CH_3CH_2X$ $(1)$ $4^{\circ}$ halide
$(B)$ $R'CH_2X$ $(2)$ $3^{\circ}$ halide
$(C)$ $R'R''CHX$ $(3)$ $2^{\circ}$ halide
$(D)$ $R'R''CR'''X$ $(4)$ $1^{\circ}$ halide

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