Structure of IF_4^+ and hybridization of iodi | vedclass

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(C) The central iodine atom in $IF_4^+$ has $7$ valence electrons. It forms $4$ bonds with fluorine atoms,leaving $1$ lone pair of electrons. Total el

Vedclass · Accepted Answer

$sp^3d$,Irregular tetrahedral

Vedclass · Answer

(C) The central iodine atom in $IF_4^+$ has $7$ valence electrons. It forms $4$ bonds with fluorine atoms,leaving $1$ lone pair of electrons. Total electron pairs = $4 	ext{ (bond pairs)} + 1 	ext{ (lone pair)} = 5$. Thus,the hybridization is $sp^3d$. According to $VSEPR$ theory,$5$ electron pairs with $1$ lone pair result in a see-saw or irregular tetrahedral geometry.

Structure of $IF_4^+$ and hybridization of iodine in this structure are

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